### See a car

Problem:

If the probability of observing a car on a highway in 20 minutes time is 609/625 then what is the probability of observing a car in 5 minutes time on the same highway (considering all the factors involved to be uniform)?

Solution:

Highlight the part between the * symbols for the answer.

*Probability of seeing a car in 20 minutes = 609/625

Hence, the Probability of seeing a car in 5 minutes = 1 - 2/5 = 3/5*

If the probability of observing a car on a highway in 20 minutes time is 609/625 then what is the probability of observing a car in 5 minutes time on the same highway (considering all the factors involved to be uniform)?

Solution:

Highlight the part between the * symbols for the answer.

*Probability of seeing a car in 20 minutes = 609/625

=> Probability of not seeing a car in 20 minutes = 1 - 609/625 = 16/625

=> (Probability of not seeing a car in 5 minutes)^4 = 16/625

=> Probability of not seeing a car in 5 minutes = (16/625)^(1/4)

=> Probability of not seeing a car in 5 minutes = 2/5

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