Finally a geometry problem for the blog. :) Thanks Dinesh! :)
We have an equilateral triangle ABC of unit side length. We want to find a curve C of the smallest length that cuts this triangle into 2 halves of equal area. Obviously, the altitude of length sqrt(3)/2 will do the job but can we do better? Note that there is no other restriction on C - it need not pass through any of the triangle vertices for instance.