tag:blogger.com,1999:blog-4115025577315673827.post69597867002309821..comments2020-05-25T13:34:36.365+05:30Comments on CSE Blog - quant, math, computer science puzzles: Penny Roll PuzzlePratik Poddarhttp://www.blogger.com/profile/11577606981573330954noreply@blogger.comBlogger12125tag:blogger.com,1999:blog-4115025577315673827.post-31250738103593585262014-10-15T07:05:12.316+05:302014-10-15T07:05:12.316+05:30The point of contact has 2*w angular velocity in f...The point of contact has 2*w angular velocity in frame of second coin thus angular displacement will also be double.Anonymoushttps://www.blogger.com/profile/02108275166641160988noreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-53118731593063051752014-04-04T09:26:49.927+05:302014-04-04T09:26:49.927+05:30The radius of rotation of the centre of outer penn...The radius of rotation of the centre of outer penny is R+R.Anonymoushttps://www.blogger.com/profile/06503740596277603928noreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-39392583882902501242013-07-08T21:28:45.418+05:302013-07-08T21:28:45.418+05:30Why is the distance pie *(R+R)? Outer penny moved ...Why is the distance pie *(R+R)? Outer penny moved half circle so distance is only pie*R, right?Earthlinghttps://www.blogger.com/profile/07133281473683565210noreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-50982479561985151762013-06-29T23:50:31.241+05:302013-06-29T23:50:31.241+05:30Perfect. ThanksPerfect. ThanksPratik Poddarhttps://www.blogger.com/profile/11577606981573330954noreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-38474404561404685642013-06-29T23:49:54.582+05:302013-06-29T23:49:54.582+05:30I am not sure if that is correct or wrong. The app...I am not sure if that is correct or wrong. The approach for sure is confusing. Simpler the better :) Please have a look at the solutionPratik Poddarhttps://www.blogger.com/profile/11577606981573330954noreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-35706044554390229502013-06-29T23:48:50.907+05:302013-06-29T23:48:50.907+05:30InterestingInterestingPratik Poddarhttps://www.blogger.com/profile/11577606981573330954noreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-45443720124317009682013-06-29T23:48:26.370+05:302013-06-29T23:48:26.370+05:30The radii of the two coins are same. SorryThe radii of the two coins are same. SorryPratik Poddarhttps://www.blogger.com/profile/11577606981573330954noreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-46888239054494798452013-04-22T02:09:12.293+05:302013-04-22T02:09:12.293+05:30On a related note, this is related to the differen...On a related note, this is related to the difference between the difference of <a href="https://en.wikipedia.org/wiki/Synodic_day" rel="nofollow">synodic</a> vs. <a href="https://en.wikipedia.org/wiki/Sidereal_time" rel="nofollow">sidereal</a> days in astronomy. The point is that in one complete "revolution" of a "planet" around its "sun", there is one fewer synodic or "solar" day than the number of sidereal days (the total number of rotations with respect to the "fixed" stars). For earth, for example, the mean solar day is 24h, while the mean sidereal days is about 23h56min. This corresponds to the usually quoted figure of 365.24 "days" in a solar years: the number of sidereal days is one more at 366.24.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-89698739745343247302013-04-22T00:10:57.533+05:302013-04-22T00:10:57.533+05:30The distance travelled by centre of outer penny fo...The distance travelled by centre of outer penny for moving half circle around the fixed penny= Pie* (R+R) = 2*Pie*R, where R is the radius. <br />Now the problem can be seen as a rotation of ring on a plane with distance to be covered by the centre of ring = 2*pie*R<br /> Assuming that it's a case of pure rolling: Distance covered by centre = Angle of rotation * Radius => Angle of rotation = 2*pie, which is 360* rotation. <br /><br />Cheers!Suyash Jainhttps://www.blogger.com/profile/14246142433651983431noreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-47602103505941024472013-04-20T16:09:58.515+05:302013-04-20T16:09:58.515+05:30Consider an alternate scenario.
Let 2 coins be ro...Consider an alternate scenario. <br />Let 2 coins be rolling across each other in opposite directions at a speed of 1 rotation per minute. A person sitting on one of the coins at the initial point of contact sees the other coin passing by at 2 rotations per second. Also exactly 1 minute past the initial moment, they will have reached their initial configuration.<br />Now stop 1 coin and roll the other coin over its circumference so that the coins reach their initial configuration in exactly 1 minute so that nothing will change for the person sitting on one of the coins. He still must see the other coin rolling past at 2 rotations per minute which is only possible if the only rolling coin is rolling at 2 rotations per minute. So after exactly 1 minute, the coin will have rotated 2 rotations to return to the initial configuration. <br />Hence 1 rotation about other coin = 2 rotations about own axis. divide by half and we have the result :)trumpcardhttps://www.blogger.com/profile/12780222271426399936noreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-86787296376890239282013-04-20T13:44:47.437+05:302013-04-20T13:44:47.437+05:30Consider a straight line. Start with two coins on ...Consider a straight line. Start with two coins on the opposite half planes with similar orientations adjacent to each other and they roll in the same linear direction (along the line). Both the coins will make respective circles. Now, warp this line around the first coin. The first coin remains stationary, but because of warping of the line, the rotation of first coin gets added to the second one and hence the full circle.Anonymoushttps://www.blogger.com/profile/00924916259781551743noreply@blogger.comtag:blogger.com,1999:blog-4115025577315673827.post-26386813227514906782013-04-20T13:43:08.285+05:302013-04-20T13:43:08.285+05:30radius of fixed penny is double than that of movin...radius of fixed penny is double than that of moving penny.Anonymoushttps://www.blogger.com/profile/15884240527025215470noreply@blogger.com